子网路切割计算.docx
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子网路切割计算.docx
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子网路切割计算
網段切割速算表
BorrwBits
(所借位元數)
PossibleSubnets
(子網段)
PossibleIPNumbersPerSubnet(IP數)
PossibleHostsPerSubnets
(ForClassc)(Host數)
1
2
128
126
2
4
64
62
3
8
32
30
4
16
16
14
5
32
8
6
6
64
4
2
7
128
2
0
Ex1)192.168.221.37/29
/29
=24+5
=借位5
=8個子網段*32子網IP地址
所以落在
192.168.221.32/29~192.168.221.40/29
可用範圍
192.168.221.33/29~192.168.221.38/29
Network
192.168.221.32/29
Broadcast
192.168.221.39/29
ex2)192.168.5.139255.255.255.224
255.255.255.224=/27
=24+3
=8*32
所以落在
192.168.5.128/27~192.168.5.160/27
可用範圍
192.168.5.129/27~192.168.5.158/27
Network
192.168.5.128/27
Broadcast
192.168.5.159/27
Q117題
hichofthefollowingIPaddressesfallintotheCIDRblockof115.64.4.0/22?
(Choosethree.)
A.115.64.8.32
B.115.64.7.64
C.115.64.6.255
D.115.64.3.255
E.115.64.5.128
F.115.64.12.128
解法:
24-22=2
=22
=4
子網段就是:
04812............
範圍是落在>4
<8
答案是看第三段欄位B是7
C是6
E是5
Answer:
BCE
Q77題
AnationalretailchainneedstodesignanIPaddressingschemetosupportanationwidenetwork.Thecompanyneedsaminimumof300sub-networksandamaximumof50hostaddressespersubnet.WorkingwithonlyoneClassBaddress,whichofthefollowingsubnetmaskswillsupportanappropriateaddressingscheme?
(Choosetwo.)
A.255.255.255.0
B.255.255.255.128
C.255.255.252.0
D.255.255.255.224
E.255.255.255.192
F.255.255.248.0
解法:
題意告訴我們說這個公司要規劃有300個子網段,並且每一個子網段需要最大IP數是50
有就是說主機(HOST)要有50個,只給了一個ClassB的Address問你下列哪一個子網路遮罩可以符合需求。
A答案
是/24最多只有254個子網段不符需求
B答案
總共借位是8+1所以總共是有29=512符合題意子網段有300個要求
可用IP數是27-2=126也符合題意
C答案
以A答案方法類推就知道不符題意需求
D答案
看最後一個欄位224=128+64+32;所以可用IP數是25-2=30不能滿足題意每個子網段要有50個HOST數要求
E答案
192=128+64;可用IP數是26-2=62滿足題意要求
子網段是210=1024也滿足題意要求
F答案
同理類推是不服提議要求
Answer:
BE
※合併子網段Summarizing要件
a.要件:
必須是偶數帶頭的連續性網段
b.帶頭的偶數可以被2n整除
c.還回n位元
Q52題
Whichtwosubnetworkswouldbeincludedinthesummarizedaddressof172.31.80.0/20?
(Choosetwo.)
A.172.31.17.4/30
B.172.31.51.16/30
C.172.31.64.0/18
D.172.31.80.0/22
E.172.31.92.0/22
F.172.31.192.0/18
解法:
題意是說下列哪兩個子網可以被合併到172.31.80.0/20
直接看IP第三段欄位
/20=24-20=4所以直接在16與8之間劃一刀
所以範圍落在80~95之間
答案就呼之欲出
Answer:
DE
※※以下例題我就不寫解題,留給學弟妹們自行練習
Q53題
Refertotheexhibit.ThenetworksconnectedtorouterR2havebeensummarizedasa192.168.176.0/21routeandsenttoR1.WhichtwopacketdestinationaddresseswillR1forwardtoR2?
(Choosetwo.)
A.192.168.194.160
B.192.168.183.41
C.192.168.159.2
D.192.168.183.255
E.192.168.179.4
F.192.168.184.45
Answer:
BE
◆Refertotheexhibit.WhatisthemostefficientsummarizationthatR1canusetoadvertiseitsnetworkstoR2?
A:
172.1.0.0/22
B:
172.1.0.0/21
C:
172.1.4.0/22
D:
172.1.4.0/24
172.1.5.0/24
172.1.6.0/24
172.1.7.0/24
E:
172.1.4.0/25
172.1.4.128/25
172.1.5.0/24
172.1.6.0/24
172.1.7.0/24
◆Refertotheexhibit.Alloftheroutersinthenetworkareconfiguredwiththeipsubnet-zerocommand.WhichnetworkaddressesshouldbeusedforLinkAandNetworkA?
(Choosetwo.)
A:
NetworkA-172.16.3.48/26
B:
NetworkA-172.16.3.128/25
C:
NetworkA-172.16.3.192/26
D:
LinkA-172.16.3.0/30
E:
LinkA-172.16.3.40/30
F:
LinkA-172.16.3.112/30
◆Refertotheexhibit.WhatIPaddressshouldbeassignedtoWorkstationA?
A:
192.168.1.143/28
B:
192.168.1.144/28
C:
192.168.1.145/28
D:
192.168.1.159/28
E:
192.168.1.160/28
◆IntheimplementationofVLSMtechniquesonanetworkusingasingleClassCIPaddress,whichsubnetmaskisthemostefficientforpoint-to-pointseriallinks?
A:
255.255.255.0
B:
255.255.255.240
C:
255.255.255.248
D:
255.255.255.252
E:
255.255.255.254
Q267題
◆TheEthernetnetworksconnectedtorouterR1inthegraphichavebeensummarizedforrouterR2as192.1.144.0/20.WhichofthefollowingpacketdestinationaddresseswillR2forwardtoR1,accordingtothissummary?
(Choosetwo.)
A:
192.1.159.2
B:
192.1.160.11
C:
192.1.138.41
D:
192.1.151.254
E:
192.1.143.145
F:
192.1.1.144
◆Anaccesslistwaswrittenwiththefourstatementsshowninthegraphic.Whichsingleaccessliststatementwillcombineallfourofthesestatementsintoasinglestatementthatwillhaveexactlythesameeffect?
A:
access-list10permit172.29.16.00.0.0.255
B:
access-list10permit172.29.16.00.0.1.255
C:
access-list10permit172.29.16.00.0.3.255
D:
access-list10permit172.29.16.00.0.15.255
E:
access-list10permit172.29.0.00.0.255.255
◆IfanethernetportonarouterwasassignedanIPaddressof172.16.112.1/20,whatisthemaximumnumberofhostsallowedonthissubnet?
A:
1024
B:
2046
C:
4094
D:
4096
E:
8190
◆Refertotheexhibit.Anewsubnetwith12hostshasbeenaddedtothenetwork.Whichsubnetaddressshouldthisnetworkusetoprovideenoughuseableaddresseswhilewastingthefewestaddresses?
A:
192.168.10.80/28
B:
192.168.10.80/29
C:
192.168.10.96/28
D:
192.168.10.96/29
◆Refertotheexhibit.WhichaddressandmaskcombinationrepresentsasummaryoftherouteslearnedbyEIGRP?
A:
192.168.25.0255.255.255.240
B:
192.168.25.0255.255.255.252
C:
192.168.25.16255.255.255.240
D:
192.168.25.16255.255.255.252
E:
192.168.25.28255.255.255.240
F:
192.168.25.28255.255.255.252
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